How does gravity and friction affect work on a slanted surface?

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SUMMARY

The discussion focuses on calculating the work done by gravity and friction on a slanted surface. The work done by gravity is expressed as Lsin(θ)mg, while the work done by friction is Lcos(θ)mgμ1. It is clarified that friction acts parallel to the ramp's surface and is a result of gravity, which always acts vertically downward. To determine the total energy expended, one must sum the work done by both forces without creating energy from nothing.

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Work, friction and gravity

Homework Statement



pic.png

Calculate the work done on the slanted portion by gravity and friction


Homework Equations



The Attempt at a Solution



Work is Fdx

F:
Gravity is L\sin\left(\theta\right)mg
Friction is L\cos\left(\theta\right)mg\mu_{1}

dx:
Friction travels along a path L, but is this also true for gravity?

Simply squaring the L's and adding them together, or subtracting friction, registers as incorrect.
 
Last edited:
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You already calculated the work done by gravity and friction. as you said
Gravity is Lsin(θ)mg
Friction is Lcos(θ)mgμ1

Friction doesn't travel, friction is a phenomenon caused by gravity, gravity always acts "straight down". The vector of the force of friction is parallel to the ramp's surface, yes. mg sin(a) is the ramp directional component of the force of gravity (imagine it as an invisible rope being pulled by invisible somebody).

assuming L is the distance the block travels down the ramp, then the above are the work done by the respective forces.

If you wanted to find out the total energy spent in this process, then you would have to add them together, don't create energy out of nothing, though.
 
Not sure why I rambled about squaring the L's.
There was a problem with the website, I hate those digital things.
Thanks anyway.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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