How does increasing temperature increase modes?

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Increasing temperature raises the average kinetic energy of gas particles, allowing them to access more energy levels and modes. For diatomic gases, there are three translational modes, two rotational modes, and potentially vibrational modes, which contribute to the total degrees of freedom. As temperature increases, the energy available to molecules surpasses the energy gaps between quantized rotational and vibrational states, enabling transitions to excited states. The Boltzmann distribution illustrates how the likelihood of occupying higher energy states increases with temperature. Ultimately, higher temperatures facilitate access to additional modes in gas molecules, enhancing their overall energy states.
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Homework Statement


Explain why the number of modes per particle increases with increasing temperature for all gases (except monatomic gases).

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The Attempt at a Solution


I am trying to use an energy argument but to be honest, I don't understand the excited state vs rest state stuff in this context. My answer would be: increasing temperature by definition increases the average kinetic energy of the substance and also increases the energy in each existing mode. If the substance has more energy, it can more easily navigate between its excited and ground state which (somehow) leads to the ability to access more modes.
 
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What kind of modes posses a gas molecule?
 
ehild said:
What kind of modes posses a gas molecule?

A diatomic gas has 3 KEtranslational modes, 2 KErotational modes. I know some diatomic gases have 2 vibrational modes too.
 
A diatomic gas molecule has one mode of vibration, but it counts twice with regard the energy. Molecules containing N atoms have 3N degrees of freedom, from those 3 is translational, 3 (2) are rotational, the others are vibrational.
You certainly know that the rotation and vibration energies are quantised. They are excited at temperatures when KBT> ΔE, the difference between the energy levels. The probability of a molecule to be at a certain energy level depends on the ratio ΔE/(KBT) You certainly have learned about Boltzmann distribution?
What do you think about the excitation energy of the rotational and vibrational modes, which are higher ?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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