Find the temperature increase of a rotating disk

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SUMMARY

The discussion focuses on calculating the temperature increase of a rotating disk subjected to a beam of right circularly polarized light. The derived formula for the temperature increase is ΔT=(IΩ/mC)(2πc/λ-Ω/2), where I is the moment of inertia, Ω is the angular velocity, m is the mass, C is the specific heat, and λ is the wavelength of the light. Key equations include Q=CmΔT and the relationships for rotational kinetic energy and photon energy. The justification for the energy terms U1 and U2 is crucial for solving the problem.

PREREQUISITES
  • Understanding of Blackbody radiation principles
  • Knowledge of rotational dynamics and moment of inertia
  • Familiarity with specific heat capacity and thermal energy equations
  • Basic concepts of photon energy and angular momentum
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  • Study the derivation of rotational kinetic energy equations
  • Learn about the relationship between angular momentum and photon properties
  • Explore advanced topics in thermodynamics related to energy transfer
  • Investigate applications of Blackbody radiation in modern physics
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Students in physics, particularly those studying thermodynamics and classical mechanics, as well as educators looking for examples of energy transfer in rotating systems.

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Homework Statement


It's a Blackbody radiation problem:
A beam of wavelength λ, in the state of right circular polarization, leads to an absorbent disk.The mass of the disk is m, it's specific heat is C, and its moment of inertia is I .The disk is initially at rest, but after a lapse of time has an angular velocity Ω. Show that the temperature increases in:

ΔT=(IΩ/mC)(2πc/λ-Ω/2)

Homework Equations


Q=CmΔT

The Attempt at a Solution


From the equation;
Q=CmΔT
I can get ΔT
ΔT=Q/Cm
And
Q=U2-U1
So
ΔT=(U2-U1)/Cm
But I don't know how to justify that;
U1=IΩ2/2 ------- Rotational kinetic energy
U2=(IΩ2πc)/λ --------- con E=hc/λ Photon energy
 
Physics news on Phys.org
Any good reference on classical mechanics should tell you the relation between angular velocity and rotational kinetic energy. Otherwise, you need to use the fact that each circularly polarized photon has an angular momentum of ħ.
 

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