How Does Mass Affect Velocity in an Elastic Collision?

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Homework Help Overview

The discussion revolves around an elastic collision problem involving two pucks on an air-hockey table, focusing on how mass affects their velocities post-collision. The original poster describes the setup, including the masses and initial velocities of the pucks, as well as their angles after the collision.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to apply conservation of momentum in both the x and y directions but encounters difficulties with the algebraic manipulation of the equations. Some participants question the correctness of the equations used, particularly regarding the representation of velocities.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's equations and pointing out potential misunderstandings in the application of momentum conservation. There is no explicit consensus yet, as participants are exploring different interpretations of the equations involved.

Contextual Notes

Participants are working under the constraints of the problem as presented, including the specific masses and angles given. There is an indication of confusion regarding the representation of initial and final velocities in the equations used.

mayanfox
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The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.023 kg and is moving along the x-axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.048 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing.

http://www.webassign.net/CJ/07_32.gif

(Puck A is 65 degrees north of east, puck B is 37 degrees south of east.)


I used MaVa = MaVa(cos 65) + MbVb(cos 37), which gives me
.1265 = .0097202Va + .03833Vb. Since the total momentum in the Y direction was zero, I also used
Va(sin 65) = Vb(sin 37)
Va = .6640Vb or Vb = 1.506Va.

Every time I plug in those numbers I get a wrong value! Am I missing some important concept, or am I just making an algebraic error?
 
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> I used MaVa = MaVa(cos 65) + MbVb(cos 37)

You Va on RHS should be different from initial Va on LHS.
 
Aah, thanks for pointing that out. I had the Va on the LHS as Vo when I did the problem, though, so it didn't change my answer.
 
> Va(sin 65) = Vb(sin 37)

Why? It should be MaVasin 65 = MbVbsin 37.
 

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