How Does Measurement Angle Affect Quantum Entanglement Probabilities?

[guillefix]

Hello, I'm planning to do my EE of IB Diploma on quantum physics and I have a doubt concerning quantum entanglement.
I know that when you have two entangled particles say, two electrons, which spin pointing in the y-axis for example, if you measure them 45º shifted in any direction you will have (1-sin45)/2 probability of getting a photon, and the other entangled electron will have then 100% probability of getting the opposite.
Now, if I measure it trough an orthogonal axis to that one measured in the first electron, will I put in the formula (1-sin(theta))/2 the angle between the y-axis and this new direction or between the axis i used to measure the other electron and this direction, i.e. (1-sin90)/2?

 

[guillefix]

I maight have stated my question in a way which is hard to understand, well i am quite a noob in QM but I am going to try to explain it with a picture I've attached. If a measure the first one through the black axis, when I measure the second one through the green axis, will I have 50% probability of getting a photon or 14.6%, which comes from (1-cos45)/2.
Thank you, the answer to this is crucial for my Extended Essay, please help me.

 

[zonde]

I maight have stated my question in a way which is hard to understand

Have not heard that you can measure electron spin by scattering photons from it. And in addition have not heard of any entanglement experiment that would measure entangled electrons despite the fact that electron spin is quite frequently used to illustrate entanglement.

I can suggest you to reformulate your question using photons and polarizers as majority of experiments are using photon polarization for entanglement measurements.