How Does Momentum Change When a Ball Bounces Off a Wall?

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yamugushi
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1. Homework Statement
A ball is rolled into a wall and bounces back at the same speed, the change in momentum is?

2. Homework Equations
Ein = Eout

3. The Attempt at a Solution
I thought it was m(v) but I got it wrong (doing test corrections ATM)

Note I'm having trouble editing, so I made a new thread, I am not trying to spam.
 
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If the velocity before impact is v, what is the velocity after impact?

(remember, velocity is a vector quantity, so direction is important)
 
So it's be -mv... but there aren't any negative answers:
I have
0
1.5
.5
2
and what I answered MV (all above are times MV as well)
 
yamugushi said:
So it's be -mv... but there aren't any negative answers:

So momentum before is mv, and momentum after is -mv, so that change in momentum is ?
 
rock.freak667 said:
is that one of the answers?

yes, the answers were:
0mv
1mv
1.5mv
.5mv
2mv
 
Just to note:

The original velocity must have been negative. The initial momentum was [tex]P_1=-mv[/tex].
Following the bounce, the final momentum is [tex]P_2=mv[/tex].
Hence the positive answer: P2-P1=2mv
Either way the magnitudes are the same.
 
Winzer said:
Just to note:

The original velocity must have been negative. The initial momentum was [tex]P_1=-mv[/tex].
Following the bounce, the final momentum is [tex]P_2=mv[/tex].
Hence the positive answer: P2-P1=2mv
Either way the magnitudes are the same.

Yes the magnitudes are the same, but it didn't have to be negative. It depends on the direction you choose as positive.