How does non-isotopic embeddings affect the homology of manifolds and knots?

  • Context: Graduate 
  • Thread starter Thread starter Bacle
  • Start date Start date
  • Tags Tags
    General
Click For Summary
SUMMARY

This discussion focuses on the relationship between non-isotopic embeddings of a subspace N in an n-manifold M and the implications for the n-th homology of M. It establishes that if there are non-isotopic embeddings of N in M, this may indicate that H_n(M) is not trivial, suggesting the presence of knots. Conversely, if H_n(M) equals zero, it implies that there is only one isotopy class of embeddings of N in M. The conversation highlights the importance of the induced map on homology from the inclusion of the subspace into the manifold.

PREREQUISITES
  • Understanding of n-manifolds and their properties
  • Familiarity with homology theory and its applications
  • Knowledge of isotopy and non-isotopy in topology
  • Concept of orientability in manifolds
NEXT STEPS
  • Research the implications of non-isotopic embeddings on homology classes
  • Study the properties of orientable submanifolds and their homology
  • Explore the concept of induced maps on homology from subspace inclusions
  • Examine examples of knots and their corresponding homology groups
USEFUL FOR

Mathematicians, topologists, and students studying algebraic topology, particularly those interested in the relationship between embeddings and homology in manifolds.

Bacle
Messages
656
Reaction score
1
Hi, everyone:

I think this should be simple, but I've been stuck for a while now:

Let M be an n-manifold and N an n-dim. subspace of M, of possibly lower dimension

than M , then M is knotted, or N is a knot in M if there are non-isotopic

embeddings of N in M.

Now:

Say there are non-isotopic embeddings of N in M. How does this affect the

n-th homology of M (n is the dimension of M) ? . Does it follow that if

H_n(M)==0 , that there are no knots, i.e., there is only one isotopy class

of embeddings of N in M? And, conversely, if f,g, are two non-isotopic embeddings

of N in M, does it follow that H_n(M) is not trivial?

Thanks .
 
Physics news on Phys.org
This is not a full answer by far, but I think we may be able to use the

map induced on homology by the inclusion of the subspace into the space.

I believe --please correct me if I am wrong -- that if the subspace N is

orientable , and the included image i(N) is a submanifold, then i(N) may be/represent

a homology class. And then the issue seems to be that of determining the

homology class of i*(N) , i'*(N) , for non-isotopic embeddings i, i'.
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K