CINA
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Homework Statement
A particle moves at speed [tex]u_{x}= +0.0c[/tex] according to an observer in the frame S.
a)Calculate the velocity of the particle, [tex]u_{x}'_{Gal}[/tex] and [tex]u_{x}'_{SR}[/tex] as measured by an observer in S'. Let [tex]\beta[/tex] range from -0.95c to +0.95c in increments of 0.05. Put your results in a table.
b)Graph [tex]u_{x}'_{Gal}[/tex] and [tex]u_{x}'_{SR}[/tex] as a function of [tex]\beta[/tex].
c) Repeat steps a and b for particles with [tex]u_{x}=+0.5c[/tex], [tex]u_{x}=+0.8c[/tex], [tex]u_{x}=+0.99c[/tex] and [tex]u_{x}=+0.9999c[/tex].
*Note* [tex]u_{x}'_{Gal}[/tex] and [tex]u_{x}'_{SR}[/tex] mean the velocities with the Galilean and the lorentz trans., respectfully.
Homework Equations
[tex]u'=\frac{u+v}{1+\frac{(u)(v)}{c^{2}}}[/tex]
The Attempt at a Solution
These are kind of dumb questions but here goes:
First of all the equation with beta in it looks like:
[tex]u'=\frac{u+v}{1+\frac{(u)(\beta)}{c}}[/tex]
Right?
Secondly, when ux=+0.0c the equation just reduces to u'x=v correct?
Thirdly, when it says graph u'Gal and u'SR as functions of beta that means beta on the horizonal and the velocities on the vertical right?