How Does Phase Affect Direction in Simple Harmonic Motion?

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SUMMARY

The discussion focuses on the relationship between phase and direction in Simple Harmonic Motion (SHM). The displacement equation x = A sin(ωt + θ) is utilized, with a specific phase of 13π/6 leading to a displacement of x = A/2. The velocity equation v = Aω cos(ωt + θ) is derived, yielding a positive velocity of v = Aω√3/2, indicating motion in the positive X direction. The discussion concludes that a phase of 17π/6 would result in motion in the negative X direction, confirming the direct correlation between phase and particle direction.

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  • Understanding of Simple Harmonic Motion (SHM)
  • Familiarity with trigonometric functions and their applications in physics
  • Knowledge of differentiation in calculus
  • Basic concepts of velocity and direction in physics
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thunderhadron
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Hi friends the problem is -

https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-ash4/430884_2656507629229_1511525381_n.jpg

Attempt -
friend as per the question I am trying to get structure of SHM,

The displacement equation x = A sin(ωt + θ) represents SHM where ωt + θ is Phase of the particle.

the phase of the particle is 13∏/6. So I putting it on the equation and getting the result -

x = A/2. So I am getting the first answer.

While differentiating the displacement equation w.r.t. time I'll get velocity - time equation.

Which will be,

v = A.ω cos(ωt + θ)

Placing here the Phase of the particle I am getting the result,

v = A.ω.√3 / 2

So i am sticking here, is it representing the direction of the particle too ?

The correct answer of this problem is option (A) as per the question.

Please friends help me in solving this Problem.

Thank you all in advance.
 
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thunderhadron said:
v = A.ω.√3 / 2

is it representing the direction of the particle too ?

Yes, the direction the particle is moving is the direction of the velocity. You got a positive velocity which indicates the velocity has a direction toward positive X.

Check that if the phase were 17π/6, then the particle would be moving in -X direction.
 
TSny said:
Yes, the direction the particle is moving is the direction of the velocity. You got a positive velocity which indicates the velocity has a direction toward positive X.

Check that if the phase were 17π/6, then the particle would be moving in -X direction.

Thank you TSny.

I got the correct answer and concept
 

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