How Does Physics Explain Forces on The Roundup Amusement Park Ride?

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Homework Statement



In an amusement park ride called The Roundup, passengers stand inside a 16.0 m-diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane.

Part A: Suppose the ring rotates once every 4.10 s. If a rider's mass is 54.0 kg, with how much force does the ring push on her at the top of the ride?

Part B: Suppose the ring rotates once every 4.10 s. If a rider's mass is 54.0 kg, with how much force does the ring push on her at the bottom of the ride?

Part C: What is the longest rotation period of the wheel that will prevent the riders from falling off at the top?


Homework Equations



Fr=nr+(Fg)r=n+mg=mv^2/r
w=v/r
1 rev=2pi radians
Might be more needed..

The Attempt at a Solution


4.10s/1 rev=1 rev/2pi radians=6.44 rad/s=w
w=v/r=6.44rad/s/8m=51.52m/s
Then do I plug it into the Fr equation? I don't have the acceleration..
Any help or how to think about it would be advantageous.
Thanks.
 
Those calcs don't look right to me.
You could do w = 1 rev/4.1s = 2*pi/4.1 = 1.53 radians/s
Or just work with v = 2*pi*r/T.
The n+mg=mv^2/r looks good.
 

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