How Does Projectile Motion Affect Speed and Angle on Impact?

Click For Summary
SUMMARY

The discussion focuses on calculating the speed and impact angle of a particle traveling between two vertical walls separated by 25 meters, moving at a constant horizontal speed of 9.2 m/s. The acceleration due to gravity is 9.8 m/s². The participant attempted to solve the problem using kinematic equations but encountered errors in their calculations, specifically in determining the final velocity and vertical component of the motion. Key equations mentioned include Vf = vi + at, d = vit + 0.5at², and vf² = Vi² + 2ad.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion principles
  • Ability to apply the Pythagorean theorem in velocity calculations
  • Familiarity with concepts of vertical and horizontal motion components
NEXT STEPS
  • Review kinematic equations for projectile motion
  • Learn how to calculate the vertical component of velocity at impact
  • Explore the relationship between time of flight and velocity components
  • Practice solving similar projectile motion problems with varying parameters
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for problem-solving strategies in kinematics.

Beanie
Messages
32
Reaction score
0

Homework Statement


A particle travels between two parallel ver- tical walls separated by 25 m. It moves to- ward the opposing wall at a constant rate of 9.2 m/s. It hits the opposite wall at the same height.

The acceleration of gravity is 9.8 m/s2 .

(IMAGE FOR CLARIFICATION ATTACHED)

a) What will be its speed when it hits the opposing wall?
b) At what angle with the wall will the particle strike?

Homework Equations


Vf=vi+at
d=vit=.5at^2
vf^2=Vi^2+2ad

The Attempt at a Solution


I've tried this problem (a) many times in many different ways, but continue to get it wrong. I have not yet been able to do problem (b) because of the lack of information (I need to complete a to do b)

Attempts:
The first way I tried was to find the time and then plug it into the second equation described above using d=25, t=2.7, a=-9.8. This resulted in a velocity of 22.52m/s. However this velocity is wrong.

The second way I tried was to find t (same as above) and then use Vx=9.2 as well as t=2.7 to calculate Vy. I found this to be 26.62. I then used the pythagorean theorem using Vx and Vy to find V. My final answer was 28.164m/s. This velocity answer was also wrong.

Any suggestions on where I am going wrong? Are there any other ways of calculating velocity?
 

Attachments

  • Screen Shot 2015-08-31 at 6.03.55 PM.png
    Screen Shot 2015-08-31 at 6.03.55 PM.png
    9.7 KB · Views: 506
Physics news on Phys.org
Start by figuring out how the final components of the velocity are related to the initial components when a projectile returns to the same height from which it was launched. Also, it seems that you have found the time of flight. Can you find the initial vertical component of the velocity?
 
Beanie said:

Homework Statement


A particle travels between two parallel ver- tical walls separated by 25 m. It moves to- ward the opposing wall at a constant rate of 9.2 m/s. It hits the opposite wall at the same height.

The acceleration of gravity is 9.8 m/s2 .

(IMAGE FOR CLARIFICATION ATTACHED)

a) What will be its speed when it hits the opposing wall?
b) At what angle with the wall will the particle strike?

Homework Equations


Vf=vi+at
d=vit=.5at^2
vf^2=Vi^2+2ad

The Attempt at a Solution


I've tried this problem (a) many times in many different ways, but continue to get it wrong. I have not yet been able to do problem (b) because of the lack of information (I need to complete a to do b)

Attempts:
The first way I tried was to find the time and then plug it into the second equation described above using d=25, t=2.7, a=-9.8. This resulted in a velocity of 22.52m/s. However this velocity is wrong.

The second way I tried was to find t (same as above) and then use Vx=9.2 as well as t=2.7 to calculate Vy. I found this to be 26.62. I then used the pythagorean theorem using Vx and Vy to find V. My final answer was 28.164m/s. This velocity answer was also wrong.

Any suggestions on where I am going wrong? Are there any other ways of calculating velocity?

Draw a dotted line on your diagram that's exactly halfway between the two walls. Start by focusing only on the part of the particle's trajectory that's between this dotted line and the wall on the right (ignoring for now the other half of the trajectory to the left). Can you use the equations you listed above to determine the vertical speed of the particle at the time it reaches the right wall?
 

Similar threads

Replies
11
Views
2K
Replies
6
Views
2K
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
23
Views
3K
Replies
10
Views
4K
Replies
4
Views
2K
Replies
11
Views
2K
Replies
8
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K