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SayedD

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- Homework Statement
- A particle is shot perpendicular to respect to the inclined plane with inclination α, with initial velocity v. Determine the value of v so that the following particle hit the incline plane with inclination β perpendiculrly. The distance between the lowest point to the launching point is a.

I have been struggling all day trying to solve this by using a method which involves tilting the ground so it makes an inclined plane with inclination α+β, here are my steps

- Relevant Equations
- Given in my attempt

So using the projectile equation I got ##a\sin (\alpha + \beta) = v\sin (\alpha + \beta)t + \frac{g\sin \beta t^2}{2}##

To find t we use the other projectile equation:

Since the horizontal velocity must be 0 for it to hit the ground perpendicularly we set the equation to be:

##0 = v\sin (\alpha + \beta) - g\sin \beta t## \\

##t = \frac{v\sin (\alpha + \beta)}{g\sin \beta}##

please help solve using this method

To find t we use the other projectile equation:

Since the horizontal velocity must be 0 for it to hit the ground perpendicularly we set the equation to be:

##0 = v\sin (\alpha + \beta) - g\sin \beta t## \\

##t = \frac{v\sin (\alpha + \beta)}{g\sin \beta}##

please help solve using this method

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