How Does Radial Temperature Vary in a Thermally Conductive Hollow Cylinder?

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SUMMARY

The discussion focuses on calculating the radial temperature variation, T(r), in a thermally conductive hollow cylinder with inner radius r1, outer radius r2, and thermal conductivity k. The cylinder is in dynamic thermal equilibrium, with temperatures T1 and T2 at its inner and outer surfaces, respectively. The key equation utilized is the heat current formula, Q = KA(T1 - T2)/L, where A represents the area, which varies with radius. The solution involves applying calculus to account for the changing area as a function of radius.

PREREQUISITES
  • Understanding of heat conduction principles
  • Familiarity with calculus, specifically integration
  • Knowledge of thermal conductivity and its implications
  • Basic concepts of dynamic thermal equilibrium
NEXT STEPS
  • Study the derivation of the heat conduction equation in cylindrical coordinates
  • Learn about the application of calculus in thermal analysis
  • Explore the concept of thermal equilibrium in multi-layer systems
  • Investigate numerical methods for solving heat transfer problems
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Students in engineering or physics, particularly those studying heat transfer, thermodynamics, or materials science, will benefit from this discussion.

Domisterwoozy
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Homework Statement


A hollow cylinder of length L has inner radius, r1, outer radius, r2 , and
thermal conductivity, k. It is in dynamic thermal equilibrium, with its interior
held at temperature T1 and its exterior at a different temperature, T2. What is the
radial temperature dependence, T(r), within the cylinder, r1 ≤ r ≤ r2 ?

Homework Equations


Heat Current = KA(T-T)/L

The Attempt at a Solution


I know heat current out equals heat current in and than you solve for T. However, I cannot figure out how to calculate the heat currents since the area is changing.
 
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You need to use calculus. Consider a very thin shell surrounding the center of the cylinder, of thickness dr. The area of one side isn't very different from the area of the other, so you can use that heat conduction equation.
 

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