How Does Relativity Explain Shorter Travel Times at High Speeds?

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Homework Help Overview

The discussion revolves around a scenario involving special relativity, specifically addressing the apparent discrepancy between the distance of 8 light years to Sirius and the astronaut's measured travel time of 6 years at a speed of 0.8c. Participants are exploring how these two measurements can coexist within the framework of relativity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to reconcile the distance and time measurements using concepts from special relativity, including time dilation and length contraction. Questions are raised about the appropriate equations to use and the astronaut's frame of reference.

Discussion Status

The discussion is ongoing, with participants providing various equations and concepts related to special relativity. Some guidance has been offered regarding the Lorentz transformation and length contraction, but there is no explicit consensus on how to proceed with the problem.

Contextual Notes

Some participants express uncertainty about the relevant equations and concepts, indicating a potential gap in understanding special relativity. There is also a mention of the need for clarity in explanations, suggesting that the problem may be challenging for those with a rudimentary understanding of the topic.

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Relativity(Light years)? PLEASE HELP!

Homework Statement


Imagine an astronaut on a trip to Siris, which is 8 light years from Earth. On arrival at Siris,
the astronaut finds that the trip lasted 6 years. If the trip was made at a constant speed of .8c, how can the 8 light year distance be reconciled with the 6 year duration?


Homework Equations


E=mc^2


The Attempt at a Solution


I don't know how to solve this question...8 light years-> 6 years. 3/.8c??
Please help!
 
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Hi SAT2400! :smile:

(try using the X2 tag just above the Reply box :wink:)
SAT2400 said:
Imagine an astronaut on a trip to Siris, which is 8 light years from Earth. On arrival at Siris,
the astronaut finds that the trip lasted 6 years. If the trip was made at a constant speed of .8c, how can the 8 light year distance be reconciled with the 6 year duration?

(e = mc2 has nothing to do with it … and i think it's Sirius :wink:)

the astronaut's measurement of the time (on his own clock) is 6 years

what is his measurement of the distance?
 


The relevant equations are:

γ=1/root(1-v2/c2)
t'=γt
x=γx'

The 6 years is measured from his frame of reference, you need to measure the distance in the same frame as well.
 


hmm, can you explain more easily/??:(

Thanks !
 
Hi SAT2400! :wink:

Do you know the Lorentz transformation equations?

(you didn't mention them in your "Relevant equations")

If not, look them up in your book. :smile:
 


root of( 1-v^2/c^2) ...is this right??

hmm...could you please explain more in detail??

Sorry,,but I still don't know how to solve this question...:(
 
SAT2400 said:
root of( 1-v^2/c^2) ...is this right??

Sort-of …

but how are you going to use it? :smile:
 


I still have no idea...T_T

If I knew how to do this,,I would have not come to this website...

SO...

Please help!

THank you very much!
 
Use x and t for the coordinates in the Earth's frame (so Sirius is at x = 8, for all t).

Use x' and t' for the coordinates in the astronaut's frame.

Start the trip at (0,0) in both frames.

What do you get? :smile:
 
  • #10


For one such as yourself, who seems to have a very rudimentary understanding of SR, I wouldn't bother with Lorentz transforms. For the question all you need to utilize is Length-contraction.

To the people traveling on the rocket, the length between Earth and Sirius is contracted to: L=L_0\sqrt{1-\frac{v^2}{c^2}} The time that they measure is then simply: t=L/v

Now you will notice that since L is contracted, it is no longer 8 light years but something shorter, and hence t can be shorter than 8 years without the rocket traveling faster than c.
 

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