How Does Tension in a Spinning Chain Relate to EM Wave Propagation Speed?

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The discussion focuses on calculating the tension in a spinning chain loop with mass per unit length \( u \) and angular speed \( w \). It establishes that the tension results from the centripetal force required for each segment of the chain, which accelerates toward the center of the loop. The tension is derived from integrating the centripetal force over the semicircle of the chain. Furthermore, it concludes that electromagnetic (EM) waves propagate at the same speed as the linear speed of the chain, linking the mechanics of the spinning chain to wave propagation.

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I need to find the tension of a spinning chain with mass per unit length u and angular speed w. I need to show that em waves on the chain travel at the same speed as the chains linear speed. please help if you can,
 
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forgot to mention its a loop of chain
 
Since it is a loop, I assume it is spinning about an axis perpendicular to the plane of the loop. Every bit of the chain of length dl has a mass dm that is accelerating toward the center of the loop. The net force on half of the loop is the integral of the required centripetal force over the semicircle. The result will be directed from the midpoint of the semicircle to the loop center. This force is supplied by the two ends of the opposite semicircle as the tension in the loop. I think this approach will get you there for finding the tension. I really don't get the part about the EM waves.
 
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