How Does the Angle of Incline Affect Train Motion Calculations?

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SUMMARY

The discussion centers on the calculations involved in determining the forces acting on a train moving at an angle of incline. The train has a mass of 1000 kg and experiences a propulsive force of 1200 N while moving horizontally with an acceleration of 0.25 m/s². The resultant force (R) acting on the train is calculated to be 950 N. The confusion arises regarding the sine component of the incline angle, which is clarified to be negligible when the incline is effectively zero degrees.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Basic knowledge of trigonometric functions, specifically sine
  • Familiarity with force resolution in physics
  • Concept of acceleration in motion
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  • Study the application of Newton's Laws in inclined plane problems
  • Learn about force resolution techniques in physics
  • Explore the effects of varying angles on motion calculations
  • Investigate the role of friction in train motion on inclines
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Students studying physics, particularly those focusing on mechanics and motion, as well as educators looking for examples of force calculations in real-world scenarios.

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Homework Statement



A train moves on a straight track at y degrees to the horizontal. The mass of the train is 1000kg. during its motion the train moves under the action of a variable propulsive force, p Newtons, and a constant resultant forceR Newtons

(a) during the first stage of motion, the train moves horizontally with acceleration 0.25 ms-2. In this stage the value of P is 1200 sow that R = 950.

Homework Equations



F=ma mabey

The Attempt at a Solution



resolved the force in direction of train got;

1200 - R - sinyo = 1000 x 0.25
950 = R + sinyo

so how can R = 950, is sinyo taken as < 0.5??
help please!
 
Physics news on Phys.org
In part (a) of the question, when it says the train is moving horizontally, it means that y=0o.
 
aaaaah you ledgend, cannot believe i didnt see that - i really am a physics goon!
 

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