How Does the Central Limit Theorem Apply to Processing Times?

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SUMMARY

The discussion centers on applying the Central Limit Theorem (CLT) to analyze processing times for cashiers handling customer orders. The mean processing time is established at 2.5 minutes with a standard deviation of 2 minutes. Participants calculated the probability of exceeding 4 hours for 100 orders and determined the minimum number of orders that can be processed in 5 hours with a 95% probability. Additionally, they explored the impact of larger orders with a mean of 5 minutes and a standard deviation of 3 minutes, factoring in a 20% probability of such orders.

PREREQUISITES
  • Understanding of the Central Limit Theorem (CLT)
  • Knowledge of probability distributions and standard deviation
  • Familiarity with statistical concepts such as mean and variance
  • Basic proficiency in statistical calculations and problem-solving
NEXT STEPS
  • Study the application of the Central Limit Theorem in real-world scenarios
  • Learn how to calculate probabilities using normal distribution
  • Explore statistical software tools for processing time simulations
  • Investigate the effects of varying sample sizes on probability outcomes
USEFUL FOR

Statisticians, data analysts, operations researchers, and anyone involved in optimizing processing times in service industries will benefit from this discussion.

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Homework Statement



The amounts of time that a cashier spends processing individual customers' orders are independent random variables with mean 2.5 minutes and standard deviation 2 minutes.

a) What is the approximate probability that it will take more than 4 hours to process orders of 100 people?

b)How many orders, at least, will be processed in 5 hours with probability 0.95?

c)Some orders are bigger and their mean processing time is 5 minutes with standard deviation of 3 minutes. If the probability of processing bigger orders is 0.2, what is the approximate probability that it will not take more than 5.5 hours to process orders of 100 customers?

Homework Equations

The Attempt at a Solution


This seems like it would involve using the central limit theorem, since no information is given about the distribution except for mean and standard deviation. I'm unsure how to apply it though.
 
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Millacol88 said:

Homework Statement



The amounts of time that a cashier spends processing individual customers' orders are independent random variables with mean 2.5 minutes and standard deviation 2 minutes.

a) What is the approximate probability that it will take more than 4 hours to process orders of 100 people?

b)How many orders, at least, will be processed in 5 hours with probability 0.95?

c)Some orders are bigger and their mean processing time is 5 minutes with standard deviation of 3 minutes. If the probability of processing bigger orders is 0.2, what is the approximate probability that it will not take more than 5.5 hours to process orders of 100 customers?

Homework Equations

The Attempt at a Solution


This seems like it would involve using the central limit theorem, since no information is given about the distribution except for mean and standard deviation. I'm unsure how to apply it though.

What do YOU think the Central Limit Theorem (not Central Limiting Theorem) says? Why do you think you can use it in this problem?
 
Last edited:

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