How Does the Delayed Neutron Fraction Influence Reactor Kinetics?

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SUMMARY

The discussion centers on the influence of delayed neutron fractions on reactor kinetics, specifically through the point kinetics equations. Given the parameters β=0.0065, λ=0.08, and Λ=0.0001, the ratio of steady-state delayed neutron concentration to total neutron concentration is calculated to be approximately 812.5. This high ratio arises because, despite delayed neutrons constituting only about 1% of total neutrons, their longer lifetimes (up to 55 seconds) allow for a greater concentration of delayed precursors in the reactor compared to the rapidly decaying neutrons (lifetime of ~0.0001 seconds).

PREREQUISITES
  • Understanding of point kinetics equations in nuclear reactor theory
  • Knowledge of delayed neutron fractions and their significance in reactor dynamics
  • Familiarity with neutron lifetimes and their impact on reactor behavior
  • Basic grasp of reactor steady-state operations
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  • Study the derivation and implications of the point kinetics equations in nuclear reactors
  • Research the role of delayed neutrons in neutron economy and reactor control
  • Examine the differences in lifetimes between prompt and delayed neutrons
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Nuclear engineers, reactor physicists, and students studying nuclear reactor dynamics will benefit from this discussion, particularly those focusing on the role of delayed neutrons in reactor kinetics and stability.

oksuz_
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Hi

Point kinetics equation with one-group delayed neutrons,

dn/dt= ((ρ-β)/∧)n+λC

dC/dt= (β/Λ)n - λC

When a reactor in steady-state operation, derivative terms would be zero. From second equation,
C/n= β/λΛ is found. For given β=0.0065, λ=0.08 and Λ=0.0001, the ratio of the steady state delayed neutron concentration to the total neutron is found about 812.5. So, what I do not understand is that the delayed neutrons is just a small fraction of the total neutrons (around 1%). How come the ratio becomes 812.5 ? Am I missing something?

Thank you ..
 
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Thank you for reply. However, I had already checked this source before I wrote this question. It gives the delayed neutron fractions for the six groups but does not answer my question.
 
oksuz_ said:
Hi

Point kinetics equation with one-group delayed neutrons,

dn/dt= ((ρ-β)/∧)n+λC

dC/dt= (β/Λ)n - λC

When a reactor in steady-state operation, derivative terms would be zero. From second equation,
C/n= β/λΛ is found. For given β=0.0065, λ=0.08 and Λ=0.0001, the ratio of the steady state delayed neutron concentration to the total neutron is found about 812.5. So, what I do not understand is that the delayed neutrons is just a small fraction of the total neutrons (around 1%). How come the ratio becomes 812.5 ? Am I missing something?

Thank you ..
Looking at the coefficients in the second equation, (β/Λ) = 65 as compared to λ=0.08, which simply means that the rate of change of C is more greatly affected by the neutron flux than by the delayed neutron fraction of the population.
 
This is an interesting problem to think about. Since the number of fraction of delayed neutrons produced by fission is fairly small (~0.65%), you would expect that the ratio of delayed precursors to the number of neutrons would be fairly small also. The difference is in the lifetimes of the neutrons and the delayed precursor. A neutron is going to have a lifetime on the order of 0.0001 sec, while the delayed precursor can have a lifetime of up to 55 seconds.

While there are many more neutrons produced by fission, the delayed neutrons stay in the system much longer. Therefore, if you take a snapshot in time, there are many more precursors in the system than there are neutrons.
 

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