How Does the Divergence of Magnetic Field Relate to Magnetizing Fields?

Click For Summary
SUMMARY

The discussion focuses on deriving the relationship between magnetic field strength in materials and the magnetizing field, specifically the equation $\nabla \cdot \mathbf{H} = -\nabla \cdot \mathbf{M}$. Participants clarify that starting from the equation $\nabla \cdot \mathbf{B} = 0$ and using the relation $\mathbf{B} = \mu_0(\mathbf{H} + \mathbf{M})$, one can manipulate the equations to arrive at the desired expression. The key step involves recognizing that $\mu_0$ is a constant, allowing it to be divided out, leading to the conclusion that $\nabla \cdot \mathbf{H} + \nabla \cdot \mathbf{M} = 0$.

PREREQUISITES
  • Understanding of vector calculus, specifically divergence operations.
  • Familiarity with magnetic field concepts, including $\mathbf{B}$, $\mathbf{H}$, and magnetization $\mathbf{M}$.
  • Knowledge of Maxwell's equations, particularly the divergence equations related to magnetic fields.
  • Basic grasp of material properties in electromagnetism, including permeability $\mu_0$.
NEXT STEPS
  • Study the derivation of Maxwell's equations in magnetostatics.
  • Explore the implications of the divergence theorem in electromagnetic theory.
  • Learn about the physical significance of magnetic permeability and its role in material magnetization.
  • Investigate advanced topics in magnetism, such as hysteresis and magnetic susceptibility.
USEFUL FOR

Physicists, electrical engineers, and students studying electromagnetism who seek to deepen their understanding of magnetic fields and their mathematical relationships.

hotel
Messages
12
Reaction score
0
Hi
I am trying to derive the relation between magnetic field strength in materials and magnetizing field from the $\mathbf B$ field. More exactly, my question is:

how do we get this expression

<br /> $\nabla \centerdot \mathbf H = - \nabla \centerdot \mathbf M$ \\ <br />

knowing

<br /> $\nabla \centerdot \mathbf B = 0$ \\ <br />

and

<br /> $\mathbf B=\mu_0(\mathbf H + \mathbf M )$ <br />
?

Anyone can guid me how the first equation is related to the 2nd and 3rd equations?

thanku
 
Physics news on Phys.org
\nabla \cdot B=\nabla \cdot {\mu}_0(H+M)=0

Do you get the idea now?
 
I 'm not sure !?

but how do we get from this:
inha said:
\nabla \cdot B=\nabla \cdot {\mu}_0(H+M)=0

to this:

\nabla \cdot H= -\nabla \cdot M

I can only see you have replaced B !

Or maybe you want me to think like this :
\nabla \cdot H=\nabla \cdot {\mu}_0H+{\mu}_0M
\nabla \cdot H=\nabla \cdot {\mu}_0M
assuming for a very small volume of material ?

or am I totally misunderstanding !?
 
\nabla \cdot {\mu}_0(H+M)=0

divide \mu_o out. you can do that since it's just a constant. then you have

\nabla \cdot H + \nabla \cdot M=0

which is what you're looking for once you move the M-term to the other side of the eq.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
608
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
984
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 22 ·
Replies
22
Views
3K