How Does the Leftmost Block Affect the Middle Block in a Force Chain?

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SUMMARY

The discussion centers on the dynamics of a system of three blocks (1.0 kg, 2.0 kg, and 3.0 kg) subjected to a 12 N force applied to the leftmost block. The correct calculation of the force exerted by the 1 kg block on the 2 kg block is determined to be 8 N, factoring in the acceleration of the system at 2 m/s². The net force acting on the 2 kg block includes both the force from the left and the opposing force from the rightmost block, which must be considered for accurate analysis.

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Homework Statement


Blocks of 1.0, 2.0, and 3.0 kg blocks are lined up on a table (1kg block being on the left, 2kg in the middle, 3kg being on the right). A rightward poiting 12 N force is applied to the leftmost block. What force does the leftmost block exert on the middle one?


Homework Equations



F=ma
a= Force applied / (m1 + m2 +m3)
a= 12N/6k= 2m/s^2

The Attempt at a Solution


Ok so this is what I did:

12N + F(1on2)=(mass of 2nd block)(acceleration)
12+F(1on2)=(2kg)(2m/s^2)
F(1on2)=8N, I got this wrong. Did i miss something, or should this force actually be negative.
 
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You got he acceleration right and that is good.

The 1 kg block exerts a force on the middle block that is to the right. The 3 kg block exerts a force on the the 2 kg block that is to the left. You don't have that one. Added together these forces are the net force on the 2 kg block.
 

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