How Does the Phase Angle in SHM Equations Affect Displacement and Energy?

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SUMMARY

The discussion centers on the phase angle (φ) in simple harmonic motion (SHM) equations and its impact on displacement and energy. It is established that for the equation x = A sin(ωt + φ), if x = +A at t = 0, then φ equals π/2. Additionally, it is clarified that the elastic potential energy (E_p) and kinetic energy (E_k) can be equal at specific points in SHM, particularly when the mass m attached to a spring oscillates with spring constant k.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM) principles
  • Familiarity with trigonometric functions and their applications in physics
  • Knowledge of energy conservation in mechanical systems
  • Basic concepts of oscillatory motion and spring constants
NEXT STEPS
  • Study the derivation of SHM equations and their graphical representations
  • Explore the relationship between potential energy and kinetic energy in oscillatory systems
  • Learn about the effects of phase angles on waveforms in SHM
  • Investigate the role of damping in simple harmonic motion
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in the mathematical modeling of oscillatory systems will benefit from this discussion.

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question 1)

If a simple harmonic oscillation is described by the function

x = A sin (wt + phi)

would phi be the opposite of what it would be for a SHM described by the function

x = A cos (wt + phi)

I.e if the graph for for x = A sin (wt + phi) , when t = 0, x = +A. would phi be equal to pi instead of 0( as it would for x = A cos (wt + phi)question 2)

For a mass m attached to a spring that undergoes simple harmonic motion, The spring
constant is k.

Does the elastic potential energy ever equal the kinetic energy at one point x?

this isn't a homework question, just my curiosity..

Thanks
 
Last edited:
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1. If [tex]x = A\sin(\omega t + \phi)[/tex] and [tex]x = +A[/tex] at [tex]t = 0[/tex], then [tex]A = A\sin(\phi)[/tex].

So [tex]\phi = \frac{\pi}{2}[/tex]
 
thanks a lot!
 

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