How does the proof of L'Hopital's rule show that the limit is equal to A?

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    L'hopital's rule Proof
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The discussion centers on the proof of L'Hôpital's Rule, specifically addressing how the condition f(x)/g(x) < α leads to the conclusion that the limit as x approaches a is equal to A. It is established that α is an arbitrary number greater than A, which implies that the limit cannot exceed A. The proof further demonstrates that by using Step 2, one can "trap" f(x)/g(x) within an interval around A, solidifying the conclusion that the limit equals A.

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modnarandom
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I've been reading over the l'Hopital's rule proof here: http://www.math.uga.edu/~pete/2400diffmisc.pdf

For the first case of the proof, how does f(x)/g(x) <α imply the limit as x -> a is also A? I understand that α is an arbitrary number greater than A, which means that the limit is less than or equal to A. But I'm not sure why equals A. Does it have something to do with t?

Thank you!
 
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modnarandom said:
I've been reading over the l'Hopital's rule proof here: http://www.math.uga.edu/~pete/2400diffmisc.pdf

For the first case of the proof, how does f(x)/g(x) <α imply the limit as x -> a is also A? I understand that α is an arbitrary number greater than A, which means that the limit is less than or equal to A. But I'm not sure why equals A. Does it have something to do with t?

Thank you!

You also have to have Step 2, as well. That shows that we can "trap" f(x)/g(x) in some arbitrary interval about A.
 
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