How Does the Step Function Relate to the Derivative of the Dirac Delta Function?

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CasualDays
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Derivative Using Dirac Delta Function

Homework Statement


Let [tex]\theta[/tex](x) be the step function:

[tex]\theta[/tex](x) be equivalent to

1, if x > 0
0, if x [tex]\leq[/tex] 0

Show that [tex]\frac{d \theta }{dx}[/tex] = [tex]\delta[/tex](x)


Homework Equations


In the previous portion I was able to prove
x [tex]\frac{d}{dx}[/tex] ([tex]\delta[/tex](x))= -[tex]\delta[/tex](x)


The Attempt at a Solution


I thought the problem was a heavyside problem but upon closer inspection, I noticed that on the heavyside step function it is 1 when x [tex]\geq[/tex] 0.

So how do I resolve this? Is there a way to change it so that it looks like a heavyside function, because that makes the problem much more convenient.:smile:
 
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tiny-tim said:
Hi CasualDays! :smile:

(have a theta: θ and a delta: δ :smile:)

Hint: what is 1 - θ(x)? :wink:


It's always the easy solutions that allude me..:biggrin: