rishi kesh Messages 35 Reaction score 3 Thread starter Dec 19, 2017 #1 Please check the image below. My algebra is bit rusty. Please explain the second step where the common factor is taken out. Attachments 1513701490469-874305.jpg 35.5 KB · Views: 920 Last edited by a moderator: Dec 19, 2017
Please check the image below. My algebra is bit rusty. Please explain the second step where the common factor is taken out.
Mark44 Mentor Insights Author Messages 38,140 Reaction score 10,730 Dec 19, 2017 #2 ##\sqrt{x^2 + x} = \sqrt{x^2 + \frac{x^2}x} = \sqrt{x^2(1 + \frac 1 x)}## Can you work out the rest?
rishi kesh Messages 35 Reaction score 3 Dec 19, 2017 #3 Mark44 said: ##\sqrt{x^2 + x} = \sqrt{x^2 + \frac{x^2}x} = \sqrt{x^2(1 + \frac 1 x)}## Can you work out the rest? That really helped.i know how to do rest.thanks:D
Mark44 said: ##\sqrt{x^2 + x} = \sqrt{x^2 + \frac{x^2}x} = \sqrt{x^2(1 + \frac 1 x)}## Can you work out the rest? That really helped.i know how to do rest.thanks:D