How Does Time Shifting Convert a WSCS Process to a WSS Process?

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MajorGrubert
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Hello everybody

I have a bit of a problem with understanding the conversion from a WSCS process [tex]X(t)[/tex] to a WSS process [tex]Y(t) = X(t - \Delta)[/tex]. With [tex]\Delta[/tex] the time shift being a uniform random variable on [tex](0,T)[/tex], independent of [tex]X(t)[/tex] and [tex]T[/tex] being the period of the mean function of [tex]X(t)[/tex]

The problem begins with the method to find the mean function of [tex]Y(t)[/tex] :

[tex]m_{Y} = E\{X(t - \Delta)\} = E\{E[X(t - \Delta)|\Delta]\} = E\{m_{X}(t - \Delta)\}[/tex]

First, and it might seem very basic, I don't get the syntax [tex]E[X(t - \Delta)|\Delta][/tex]

And second, why by averaging the mean of the WSCS process over its period [tex]T[/tex] would we get the mean function of the WSS process ?

If I understand that I could understand the same kind of process used to find the autocorrelation function of [tex]Y(t)[/tex] from the autocorrelation function of [tex]X(t)[/tex]

Please help me !
 


On this forum, the LaTex will appear more gracefully if you use the "itex" tag when you want the expression to appear inline with the text.

Code:
the conversion from a WSCS process [itex] X(t) [/itex] to a WSS process [itex] Y(t) = X(t - \Delta) [/itex].

the conversion from a WSCS process [itex]X(t)[/itex] to a WSS process [itex]Y(t) = X(t - \Delta)[/itex].

I don't get the syntax [tex]E[X(t - \Delta)|\Delta][/tex]

On my screen the square brackets are hard to distinguish from the vertical bars. My interpretation is that it is a "conditional expectation". Roughly speaking, compute the expected value of [itex]X(t - \Delta)[/itex] for one particular value of [itex]\Delta[/itex].

So:

[tex]E( E\{X(t-\Delta)| \Delta\}) = \int_{y=0}^{y=T} \bigg( \int_{-\infty}^{\infty} (x) p(X(t-y)=x)| \Delta=y) dx \bigg) p(\Delta=y) dy[/tex]