How Does Torque Maintain Equilibrium in a Ladder Supported by Two People?

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SUMMARY

The discussion focuses on the equilibrium of a uniform ladder supported by two individuals, where one person supports the ladder at point A and the other at point B. Initially, the supporting force at A is calculated to be 120N, leading to a supporting force of 280N at B. Upon the release of the ladder by person A, the torque required by person B to maintain horizontal equilibrium is determined to be 300Nm. The conversation clarifies the distinction between torque and moment, emphasizing that torque is necessary to counterbalance the weight of the ladder when one support is removed.

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Homework Statement


A uniform ladder AC weight 400N & length 3.5 m is held horizontally by 2 people. One person supports at A and the other at B, a distance 1m away from C.
1. Calculate the supporting force provided by the person at A. (I managed to do this one and the answer is 120N)
2. The person at A releases the ladder. Calculate the torque which the person at B must provide in order to keep the ladder horizontal.

The diagram can be found here (scroll down to see diagram)
http://www.thestudentroom.co.uk/showthread.php?t=1780861

I am having some problems with question 2. The answer to question 2 is 300Nm :)

Homework Equations





The Attempt at a Solution


It is known that the supporting force at A is 120N when the end of the ladder (at A) has not been released, this means that the supporting force at B is 280N (400N-120N). However, I do not understand why the question asked for torque, I thought torque would require two forces which form a couple? Or am I having a gross misconception? Or does the torque here refers to the moment? If the ladder is horizontal, the ladder should be in equilibrium, hence the total upward forces should equal to the total downward forces. So does this mean that the new supporting force at B should also be 400N?

Please include explanations along with your solution, thanks a million! :D
 
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jiayingsim123 said:

The Attempt at a Solution


It is known that the supporting force at A is 120N when the end of the ladder (at A) has not been released, this means that the supporting force at B is 280N (400N-120N). However, I do not understand why the question asked for torque, I thought torque would require two forces which form a couple? Or am I having a gross misconception? Or does the torque here refers to the moment? If the ladder is horizontal, the ladder should be in equilibrium, hence the total upward forces should equal to the total downward forces. So does this mean that the new supporting force at B should also be 400N?

Please include explanations along with your solution, thanks a million! :D

With the system as shown in the diagram, the ladder is in equilibrium. So all three forces help to provide that equilibrium.

When person A let's go, the system is not in equilibrium anymore. The sum of the moments about any point is not zero anymore.

For it to remain in equilibrium, the person at B will need to provide a torque to balance out the torque due to the weight.
 

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