How Does U-Substitution Using Tan(x/2) Simplify Trigonometric Integrals?

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SUMMARY

The discussion focuses on using the substitution \( u = \tan(x/2) \) to simplify trigonometric integrals, specifically transforming \( \sin x \) and \( \cos x \) into expressions involving \( u \). The key results derived are \( \sin x = \frac{2u}{u^2 + 1} \) and \( \cos x = \frac{1 - u^2}{u^2 + 1} \). Participants emphasize the importance of understanding the identity \( 1 + \tan^2(\alpha) = \frac{1}{\cos^2(\alpha)} \) to facilitate this substitution. The discussion concludes with a suggestion to visualize the problem using a right triangle to derive \( \sin(x/2) \) and \( \cos(x/2) \).

PREREQUISITES
  • Understanding of trigonometric identities, particularly \( \sin(2\theta) \) and \( \cos(2\theta) \).
  • Familiarity with the tangent half-angle substitution.
  • Basic knowledge of integral calculus and trigonometric integrals.
  • Ability to manipulate algebraic expressions involving trigonometric functions.
NEXT STEPS
  • Study the derivation of trigonometric identities, especially \( \sin(2\theta) = 2\sin(\theta)\cos(\theta) \).
  • Learn about the tangent half-angle substitution and its applications in integration.
  • Explore the use of right triangles in deriving trigonometric values.
  • Practice solving integrals involving trigonometric functions using substitutions.
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Students studying calculus, particularly those focusing on integration techniques involving trigonometric functions, as well as educators looking for effective methods to teach these concepts.

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Homework Statement



Im trying to figure out how to get sinx=2u/(u^2+1) and cosx=(1-u^2)/(u^2+1). In order to solve the problem integral sinx/(sinx+cosx)

Homework Equations


use tan(x/2) to solve the problem.

The Attempt at a Solution


all I can get to is u=sin(x/2)/cos(x/2)-------2u=sinx/cosx
I don't understand how we can get the u^2+1 on the bottom. All we need is the give the u-substitution but i donno how to do it.
 
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So, we let u=\tan(x/2). Then we need to evaluate

\frac{2u}{1+u^2}=\frac{2\tan(x/2)}{1+\tan^2(x/2)}

Try to prove the following formula first:

1+\tan^2(\alpha)=\frac{1}{\cos^2(\alpha)}
 
I just want to know how you get sinx=2u/(u^2+1) and cosx=(1-u^2)/(u^2+1) from tan(x/2). After that I can use that to plug in the integral sinx/(sinx+cosx) to make the equation solvable.
 
I don't quite get it. Just substitute u=\tan(x/2) and you'll see that the equation is correct...
 
thanks, i got it now
 
Hello,

Another easier approach :

You have u=tan(x/2), draw the triangle.

Now, sin(x)=sin( 2 (x/2) ) = 2 sin(x/2) cos(x/2) , get sin(x/2) & cos(x/2) from your triangle.
cos(x)=cos( 2 (x/2) ) = [ cos(x/2) ]^2 - [ sin(x/2) ]^2
 
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