How Does Voltage Influence Electron Motion in a Magnetic Field?

AI Thread Summary
Voltage influences electron motion by accelerating the electron to a specific velocity, which is derived from the equation .5mv^2 = qV, where q is the charge and V is the voltage. In a magnetic field, the force acting on the electron is calculated using F = qvB, where B is the magnetic field strength. The maximum magnetic force occurs when the electron moves perpendicular to the magnetic field, while the minimum force is zero when the electron moves parallel to the field. Understanding these concepts is essential for calculating the forces acting on charged particles in magnetic fields. The distinction between F, F.max, and F.min is crucial for analyzing electron behavior in different orientations relative to the magnetic field.
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An electron is accelerated through 2550 V from rest and then enters a region where there is a uniform 1.70 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron?
F = qvB
F = (mv^2)/R
F = qE

I know q = 1.6*10^-19, B = 1.7, and V = 2550. In order to use F = qvB, all I need is the velocity. I guess I'm just not seeing how the 2550 V is relating into this whole scheme of things. Also, I'm not sure why there is is going to be a F.max and a F.min, and not just one F?

Appreciate any help.

Thanks much,
Kyle
 
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Ok, I figured out F.max by just saying:

.5mv^2 = qV

F.max = qvBHowever, I'm not sure what F.min is and the difference between F, F.max, and F.min?
 
Bump. Any idea on the F.minimum?

Thanks,
kyle
 
Minimum

The minimum is 0, when the particle is moving in the direction of or opposite the direction of the magnetic field
 
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