How Does Water Pressure Affect Buoyancy in Different Submerged Objects?

Click For Summary
SUMMARY

This discussion focuses on the relationship between water pressure and buoyancy in submerged objects, specifically air-filled balls and solid objects in a tube at a depth of 10 feet. The pressure exerted on the uppermost ball to displace it from the tube is determined by the water pressure at that depth, which is approximately 4.33 psi (pounds per square inch). The buoyancy force acting on the balls is equal to the weight of the water displaced by them, and this force must be considered when calculating the total force required to push the balls or solid objects deeper into the water.

PREREQUISITES
  • Understanding of buoyancy principles and Archimedes' principle
  • Knowledge of hydrostatic pressure calculations
  • Familiarity with the concept of density and volume displacement
  • Basic physics concepts related to forces and equilibrium
NEXT STEPS
  • Research hydrostatic pressure calculations at various depths in fluids
  • Study Archimedes' principle and its applications in buoyancy
  • Explore the effects of object shape on buoyancy and displacement
  • Learn about fluid dynamics and the behavior of submerged objects
USEFUL FOR

This discussion is beneficial for students studying physics, particularly those focusing on fluid mechanics, as well as educators and anyone interested in understanding the principles of buoyancy and pressure in submerged environments.

alibaba2
Messages
31
Reaction score
0
hi, I'm stuck on a homework task I've been given..help will be greatly appreciated:))

image link: img168.imageshack.us/my.php?image=image1vn3.jpg

setup is as follows:
image 1 . a tube (1ft diameter) submerged in water. tube is filled with air-filled balls( 1ft diameter) which tightly fit all the way in the tube, leaving only small water pockets in between.

image 2. same tube. solid object , no water gaps.

at 10ft depth, what would be the pressure that will have to be exerted on the uppermost ball in order to push the first ball out of the tube . i can't understand the buoyancy issue...??will it be equal to the sum of the buoyancy forces of all the balls?or will it be the pressure (kg/cm2) at a depth of 10ft. ...bit of a mess:)

what will be the difference if the shape was like that in image2? i want to calculate what would be the force to push the object 1ft deeper into the water outside the tube??

thank you

 
Physics news on Phys.org
anybody??

ANybody?
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
5
Views
2K
Replies
7
Views
3K
  • · Replies 25 ·
Replies
25
Views
6K