How Does WolframAlpha Calculate the Sum of (2n+1)/(n(n+1)(n+2))?

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The discussion revolves around understanding how WolframAlpha calculates the sum of (2n+1)/(n(n+1)(n+2)) from n=1 to infinity, which results in 5/4. Users seek clarification on deriving the partial sum formula to understand the final result better. There is a request for guidance on obtaining the partial sum formula, as some participants express difficulty in deriving it. The conversation emphasizes the importance of the partial sum formula in reaching the final answer. Overall, the thread highlights a collaborative effort to unpack the mathematical reasoning behind the calculation.
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Did you try to get the derivation of the partial sum formula? Once you have that the final result is obvious.
 
Thank you very much for the quick answer, but:

mathman said:
Did you try to get the derivation of the partial sum formula? Once you have that the final result is obvious.

how do you get the partial sum formula? I can't seem to get that
 
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