How Efficient is a Carnot Air Conditioner at 76°F Indoors and 96°F Outdoors?

[noname1]

A Carnot air conditioner takes energy from the thermal energy of a room at 76°F and transfers it as heat to the outdoors, which is at 96°F. For each joule of electric energy required to operate the air conditioner, how many joules are removed from the room?

Attempt at problem

76 + 273 = 349
96 + 273 = 369

COP = energy removed / elec energy required

COP = 349 / (369 - 349) = 17.45

17.45 = energy removed / 1 Joule

the system is always saying that my answer is incorrect but i can't figure out what

 

[vela]

Your temperatures are in Fahrenheit, not Celsius, so you're converting them to absolute temperatures incorrectly. The rest looks okay, though.

 

[noname1]

shoot i didnt notice that but anyways converted now but the system still says i got the wrong answer


(5/9)(76-32) = 297.44
(5/9)(96-32) = 308.56

COP = energy removed / elec energy required

COP = 308.56 / (308.56 - 297.44) = 27.75

27.75 = energy removed / 1 Joule

i can't find out what's wrong

 

[vela]

You're using the wrong temperature in the numerator.