How far above the top of a fence?

  • Thread starter Thread starter noaster
  • Start date Start date
Click For Summary

Homework Help Overview

The problem involves a ball being kicked towards a fence, requiring calculations related to its motion, including net force, time to reach the fence, height above the fence, and vertical velocity at the fence. The subject area includes kinematics and dynamics, particularly projectile motion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the height of the ball as a function of time and suggest using the time to reach the fence to find the vertical position. There are attempts to reconcile different values for the height above the fence, with some participants questioning the accuracy of their calculations.

Discussion Status

Some participants have confirmed their calculations for the time to reach the fence and the vertical component of velocity, while others express uncertainty about the height above the fence, indicating a need for precision in their calculations. Multiple interpretations of the problem are being explored, particularly regarding the accuracy of the results.

Contextual Notes

Participants note the importance of maintaining high precision in calculations, as small inaccuracies can significantly affect the final answer. There is also a hint that the diameter of the ball is negligible, which may influence the height calculation.

noaster
Messages
1
Reaction score
0
A ball of mass 0.4 kg, initially at rest, is
kicked directly toward a fence from a point
20 m away, as shown below.
The velocity of the ball as it leaves the
kicker’s foot is 19 m/s at angle of 61 ◦ above
the horizontal. The top of the fence is 12 m
high. The kicker’s foot is in contact with the
ball for 0.04 s. The ball hits nothing while in
flight and air resistance is negligible.
The acceleration due to gravity is 9.8 m/s2

1. Determine the magnitude of the average
net force exerted on the ball during the kick.
Answer in units of N.

2. Determine the time it takes for the ball to reach the plane of the fence. Answer in units of s.

3. Hint: Consider the diameter of the ball to be
negligible. How far above the top of fence will the ball
pass? Answer in units of m.

4. What is the vertical component of the velocity
when the ball reaches the plane of the fence?
Answer in units of m/s.

I have gotten all of the parts except 3. I have tried submitting .969, 1.148, and .8377 nut they are all wrong

1 is 190
2 is 2.1739
4 is -4.68649

THESE THREE ARE RIGHT FOR SURE. I SUBMITTED THEM
 
Last edited:
Physics news on Phys.org
What's the height of the ball as a function of time?
 
noaster said:
A ball of mass 0.4 kg, initially at rest, is
kicked directly toward a fence from a point
20 m away, as shown below.
The velocity of the ball as it leaves the
kicker’s foot is 19 m/s at angle of 61 ◦ above
the horizontal. The top of the fence is 12 m
high. The kicker’s foot is in contact with the
ball for 0.04 s. The ball hits nothing while in
flight and air resistance is negligible.
The acceleration due to gravity is 9.8 m/s2

1. Determine the magnitude of the average
net force exerted on the ball during the kick.
Answer in units of N.

2. Determine the time it takes for the ball to reach the plane of the fence. Answer in units of s.

3. Hint: Consider the diameter of the ball to be
negligible. How far above the top of fence will the ball
pass? Answer in units of m.

4. What is the vertical component of the velocity
when the ball reaches the plane of the fence?
Answer in units of m/s.

I have gotten all of the parts except 3. I have tried submitting .969, 1.148, and .8377 nut they are all wrong


I am not sure how you got those values but I get something different

Find the time to reach the fence (using the motion along X). Then plug that time in the Y equation.
 
I agree with your time of 2.17 s. I got 12.9 - 12 for the height, which agrees with your first answer to my 1 digit accuracy. I suspect the difficulty is in accuracy. That 12.9 - 12 kills two digits of accuracy so if you need 3 digit accuracy in the final answer you need to do everything to 5 or 6 digits. Even g = 9.81 doesn't cut it.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
15K
  • · Replies 11 ·
Replies
11
Views
7K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K