- #1

apiwowar

- 96

- 0

so i solved for the initial velocity which is 33.13m/s

the i broke it up into its x and y components

Vx=23.43 m/s

Vy = 23.43 m/s

since the range is 112m i found the time that it takes for the ball to go 112m

t= x/Vx = 112m/23.43m/s

i then found the time it takes to 102 m using the same method and got 4.35s

so to find the height of the ball i did x=(23.43)(4.35)+1/2(9.8)(4.35)^2 = 9.2m

so i thought that it would be 2.91m above the fence but that's wrong.

where did i go wrong/?