- #1

warmfire540

- 53

- 0

Well i have:

W=1/2kx^2

W=55080J

W=U(potential energy) so i know the potential energy of the spring is 55080

Energy is conserved..so after the spring has decompressed all the energy is in the block..which is now kinetic

K=1/2mv^2

55080=1/2(1.5)v^2

so Vi=406.5m/s ?? that seems pretty darn high, this is just the initial velocity right?

so Vf=0

friction = 3.7N

F=ma

Vf^2=vi^2+2ax

I assume I'm using these equations..but am not sure how i arise to get accel or if I'm on the right track..