How Far Does a Block Travel Up an Incline Before Stopping?

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SUMMARY

The discussion focuses on calculating the distance a block travels up a 30-degree incline before stopping, given an initial velocity of 3 m/s and a coefficient of friction of 0.5. The forces acting on the block include gravitational force and friction, leading to the equation mgsin(30) - (0.5)*mgcos(30) = ma. The user initially miscalculated the horizontal force of gravity, which is crucial for determining the correct acceleration and, subsequently, the stopping distance.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of kinematic equations, specifically v^2 = (v_0)^2 + 2a(x - x_0)
  • Familiarity with forces on an incline, including gravitational and frictional forces
  • Basic trigonometry for resolving forces at angles
NEXT STEPS
  • Review the calculation of forces on inclined planes, focusing on gravitational components
  • Study the effects of friction on motion, particularly in inclined scenarios
  • Practice solving similar problems involving kinematics and forces on inclines
  • Explore the implications of mass cancellation in force equations and its impact on acceleration
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined planes, as well as educators looking for examples of force analysis in motion problems.

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Homework Statement


A block of unknown mass is sent up an incline plane of 30 degrees with an initial velocity of 3 m/s. The coefficient of friction is 0.5. Find the distance the block travels up the incline before it stops.


Homework Equations


F = ma
v^2 = (v_0)^2 + 2a(x - x_0)


The Attempt at a Solution


So the vertical forces of the incline are the normal force which is equal to mgcos(30). Therefore, the force of friction is (0.5)*mgcos(30).

So taking going up the incline to be positive, we have mgsin(30) - (0.5)*mgcos(30) = ma. We can cancel out the masses. So then we have acceleration = ((2-sqrt(3))(9.8)/4. This turns out to be positive, but it should be negative because the friction should overcome gravity eventually (maybe not, but this problem is implying it). What did I do wrong so far?
 
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Never mind, I calculated the horizontal force of gravity incorrectly
 

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