How Far Does a Golf Ball Travel When Struck at 30 Degrees?

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SUMMARY

The discussion focuses on the physics of a golf ball struck at a 30-degree angle with an initial velocity of 11 m/s. The calculations reveal that the horizontal distance traveled by the golf ball is 10.9 meters, and the maximum height attained is 1.54 meters. To achieve a distance of 100 meters with the same trajectory, the required initial velocity is calculated to be 33.7 m/s. The equations used include the range formula (u²sin2θ/g) and the height formula (u²sin²θ/2g).

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bobmarly12345
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Homework Statement


a golf ball is struck at an angle of 30 degree with respect to the horizontal, at a velocity of 11m/sec. the golf course is perfectly level and the golf ball stops instantaneously when it hits the ground.
a) determine the horizontal distance traveled by the golf ball
b) determine the maximum height attained by the golf ball
c) if the golf ball is to travel a distance of 100m using the same initial trajectory, determine the required initial velocity

Homework Equations


(u²sin2theta)/g
(u²sin²theta)/2g
sqrt((rg)/sin2theta)



The Attempt at a Solution


vertical component = 11sin30
horizontal " = 11cos30

a) range = [11²xsin(2x30)]/9.81 = 10.9m
b) height = [(11²xsin(30)²)/2x9.81 = 1.54m
c) 100m/s
sqrt((100.9.81)/sin(2x30))=33.7m/s

thats what I've done, i think its right but would like it if someone could check if I'm doing it right? whoever is hitting this golf ball doesn't seem very good if they're hitting it 10.9m :)
cheers
 
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