How far does his center of mass move up

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SUMMARY

In the discussion, the calculation of how far Dave Johnson's center of mass moves upward during his high jump is addressed. Given his vertical velocity component of 6 m/s, the conversion of kinetic energy into potential energy is the key principle for solving this problem. Using the formula for gravitational potential energy, the height can be determined by equating kinetic energy (1/2 mv²) to potential energy (mgh). This results in a maximum height of 1.83 meters for his center of mass.

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  • Understanding of kinetic and potential energy concepts
  • Familiarity with the equations of motion in physics
  • Basic knowledge of gravitational acceleration (9.81 m/s²)
  • Ability to manipulate algebraic equations
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  • Study the principles of energy conservation in physics
  • Learn how to apply the equations of motion for vertical jumps
  • Explore the effects of initial velocity on jump height
  • Investigate real-world applications of kinetic and potential energy in sports
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Physics students, sports scientists, coaches, and anyone interested in the mechanics of athletic performance and biomechanics.

chevyboy86
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Dave Johnson, the bronze medallist at the 1992 Olympic decathalon in Barcelona, leaves the ground at the high jump with vertical velocity component 6 m/s. How far does his center of mass move up as he makes the jump?

I've got nothing for info how do I solve this?
 
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Think conversion of kinetic energy into potential energy!
 

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