Calculate velocity of stopping car

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Homework Help Overview

The problem involves a car that begins decelerating from an initial velocity of 20 m/s and travels a distance d before coming to a stop. The task is to determine the car's velocity at the halfway point, d/2.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants suggest assuming constant deceleration. Others explore the relationship between initial velocity, final velocity, distance, and acceleration, questioning how to approach the problem without knowing acceleration.

Discussion Status

The discussion includes various interpretations of the problem, with participants offering different methods and questioning the necessity of time in the solution. Some guidance has been provided regarding relevant equations, but no consensus has been reached on a single approach.

Contextual Notes

Participants note the absence of information regarding acceleration, which complicates the problem-solving process. There is an emphasis on working with the given initial conditions and the relationship between variables.

Lizi
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Homework Statement


A car moving at 20m/s starts decelerating, travels distance d, and stops. Find the car’s velocity at distance d/2.

Homework Equations

The Attempt at a Solution


my brain is fried. I feel like I’m missing something obvious but I just don’t get it.
 
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I suppose you should assume a constant deceleration
 
Lizi said:

Homework Statement


A car moving at 20m/s starts decelerating, travels distance d, and stops. Find the car’s velocity at distance d/2.

Homework Equations

The Attempt at a Solution


my brain is fried. I feel like I’m missing something obvious but I just don’t get it.

It was a bit of a brain 'fry' !

Time 'reversing' so that we have acceleration from 0 m/s instead of deceleration from 20 m/s:

$$ d = ½at^2 ⇒ \frac{d}{2} = ½a\left({\frac{t}{\sqrt{2}}}\right)^2 ⇒v=\frac{at}{\sqrt{2}}$$
 
neilparker62 said:
It was a bit of a brain 'fry' !

Time 'reversing' so that we have acceleration from 0 m/s instead of deceleration from 20 m/s:

$$ d = ½at^2 ⇒ \frac{d}{2} = ½a\left({\frac{t}{\sqrt{2}}}\right)^2 ⇒v=\frac{at}{\sqrt{2}}$$

But since you don't know ##a## you can't obtain ##t##, so you stick with two unknowns. I think the question should be solved independent of the time ...
 
Edit: This cross posted with some of the above;

It gives you the initial velocity (u) and asks you to find the cars velocity (v) after traveling a distance (s = d/2). What equation relates u,v,s and a?

You aren't given the acceleration (a) but you can work it out from the first part of the problem statement.
 
stockzahn said:
But since you don't know ##a## you can't obtain ##t##, so you stick with two unknowns. I think the question should be solved independent of the time ...
at = ?
 
neilparker62 said:
at = ?

Still, I think the medthod @CWatters proposes is the preferred one. Additionally it should be the OP's task to solve it ...
 
guys, I figured it out using the d=(v2-u2)/(2a) formula.
Thank you all so much
 
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