How Far Is the Dog from the Shore After Walking on the Boat?

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SUMMARY

The discussion centers on solving the "snoopy problem," where a dog on a boat walks a distance L towards the shore. The key equation used is the center of mass equation: m1r1 + m2r2 = (m1 + m2)rcm. The challenge lies in determining the new positions of the dog and the boat after the dog walks, as both the dog and the boat move, affecting the overall distance from the shore. The solution involves setting the center of mass of the system (dog and boat) and equating it to the initial center of mass to find the new distance from the shore.

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Homework Statement



All right, so: dog on a boat. It's the snoopy problem. There's a boat floating on some water, and there's a dog on the end - he starts at X away from the shore. Then, he walks a length L across the boat towards the shore. How far is he away from the shore at the end?

Homework Equations



m1r1 + m2r2 = (m1 + m2)rcm

The Attempt at a Solution



As far as I can get is to set the center of mass as X at the beginning.

Mboat * Xi + Mdog * Xi = (Mboat + Mdog)Xi

and then the dog walks L towards the shore and I am not sure how to set this equation up.

Mboat * (Xi + L) + Mdog * (Xi - L) = (Mboat + Mdog) Xi

See, I know the center of mass doesn't move, because the system is isolated and the only forces are internal. However, I don't know how to make the positions relative - this equation would work if the problem literally stated he walks a length L towards the shore (his new position obviously would be Xi - L) but it says he walks length L down the boat, which means the boat moves too and he doesn't quite make the distance L from an external observer's point of view.
 
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In the given problem, the center of mass of boat and dog are not at Xi. Only CM of dog is at Xi. Let d be the CM of boat.
Now CM of (boat + dog) will be -------(1)
As you have said CM of the system remains the same. So when dog walks a length L towards the shore, CM of boat must move away from the shore. Let this be x. Now new position of the dog is [(X - L) + x] and new CM of boat wiil be (d + x). Find the CM of ( dog + boat) in this position and equate it to eq(1) and find x.
 

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