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Center of Mass boat distance from shore what am I doing wrong?

  1. Mar 16, 2012 #1
    Problem: A symmetrical rowboat, mass M = 116 kg, length L = 6.89 m, points toward the shore. A man, mass m = 90 kg, stands in the back of the boat, distance d = 35.7 m from the shore. If the man now walks to the front of the boat, how far will he be from the shore?

    Here is what I did:

    Selected 0 as origin at shoreline:

    Center of mass when man is in back of boat = [(90)(6.89) + (116)(3.445)] / (90 + 116) = 4.95 meters

    When man is in front of boat he is distance d from shore and boat is distance d + 3.445:
    Center of mass = [90d + 116(d + 3.445)] / (90 + 116) = 4.95
    d = 3.01; so when man moves from back to front displacement is 3.01 m

    So distance from shore is 35.7 + 3.01 = 38.7 m. But this answer is wrong. So what am I doing wrong???



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Mar 16, 2012 #2

    PeterO

    User Avatar
    Homework Helper

    The man was walking towards the shore, not away from the shore, so he will be closer that 35.7, not further.
     
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