How far the aircraft slides before it comes to rest ?

[Colin19]

Homework Statement

An aircraft has to make an emergancey landing on a runway
without landing gear , if the aircraft lands at 40 m\s-1
and μ is 0.5 ,
How far the aircraft slides before it comes to rest ?

Homework Equations

X=2 μ g \ v2

The Attempt at a Solution

2 x 0.5 \ 20 = 2 m ?
Using some website calculater result was : 1600 m
I'm terribly lost

 

[Colin19]

Any help please

 

[azizlwl]

Then compare with a car, do you think they equally stop at same distance.?

 

[Quantum Mind]

Here's a similar thread:

https://www.physicsforums.com/showthread.php?t=274670

 

[asteriatic]

and confused

I would approach this problem by first understanding the situation and the given information. The problem states that an aircraft has to make an emergency landing on a runway without landing gear, and we are given the initial velocity (40 m/s) and the coefficient of friction (μ=0.5).

To calculate the distance the aircraft slides before coming to rest, we can use the equation X=2μg/v², where X is the distance, μ is the coefficient of friction, g is the acceleration due to gravity, and v is the initial velocity.

Plugging in the given values, we get X=2(0.5)(9.8 m/s²)/(40 m/s)², which simplifies to X=0.245 m. This means that the aircraft will slide approximately 0.245 meters before coming to rest.

However, this calculation assumes that the aircraft slides in a straight line, which may not be the case in a real-life scenario. Other factors such as wind, surface conditions, and the pilot's actions can also affect the distance the aircraft slides before coming to rest. Therefore, this calculation should be taken as an estimate and not an exact value.

In conclusion, the distance the aircraft slides before coming to rest can be estimated using the given information and the equation X=2μg/v². However, in a real-life scenario, other factors may also play a role in determining the exact distance.