- #1

- 1

- 0

The initial velocity of the ball is 1.49 m/s

The coefficient of friction between the ball and the green is .0409

The mass of the ball is 0.046kg

The diameter of the ball is 42.6mm

The fact that the ball is rolling, means that the movement is a combination of translational velocity and rotational velocity. However I am struggling to understand the method to calculate the rotational velocity and implement it within the equation.

MOI of a solid sphere = 2/5 mr^2

I have taken this frictional value from a textbook, but am not sure whether I need to apply this value to calculate the rate of acceleration, or calculate an alternative rolling resistance value?

My attempt thus far (only taking translational movement into account):

Acceleration = mgu/m = gu = 9.81 * 0.046 = 0.4 m/s^2

Displacement = s = v^2 / 2a = 1.49^2 / 2 * .4 = 2.775 m

If anyone would be able to help/guide me, I would be most grateful.

Regards, George