How Far Will the Pendulum Swing After a 250m/s Rifle Bullet Buried Itself?

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Homework Help Overview

The problem involves a 20g rifle bullet traveling at 250m/s embedding itself in a 3.8kg pendulum, which is suspended from a 2.3m-long string. The question seeks to determine how far the pendulum swings horizontally after the bullet impacts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of momentum and energy as relevant principles. Some mention formulas that could be useful for solving the problem, while others express confidence in their understanding of the concepts involved.

Discussion Status

The discussion appears to have progressed with some participants providing formulas and approaches related to the conservation laws. One participant indicates they have reached a conclusion, but there is no explicit consensus on the method or final outcome.

Contextual Notes

There may be assumptions regarding the ideal conditions of the pendulum and the bullet's impact, as well as the absence of external forces or friction in the scenario. The problem is framed within the context of a physics textbook, which may impose certain constraints on the approach taken.

mrtkawa
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i need a help on this problem

a 20g rifle bullet traveling 250m/s buries itself in a 3.8kg pendulum hanging on a 2.3m-long string. how far does th ependulum swing horizontally?

Physics 3rd edition Douglas C. Giancoli
 
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also this formuls might be handy

V1=(m+M)/mv'=(m+M)/√2gh

g=gravity
 
The conservation of momentum

[tex](M+m)v=mv_0[/tex]

The conservation of energy

[tex]\frac{1}{2}(M+m)v^2=(M+m)gl(1-\cos\theta)[/tex]

The horizontal displacement

[tex]\Delta x=l\sin\theta[/tex]

Solving the equation will give you the answer[/color]
 
thanks i got it
 

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