How Fast Does a Boulder Roll Downhill After a Tremor?

[etSahcs12]

Homework Statement

A slight Earth tremor causes a large boulder to break free and start rolling down the mountainside with a constant acceleration of 5.2 m/s^2. What is the boulder's velocity after 5.0s.

Homework Equations

I used: v2 = v1 + a x Δt

The Attempt at a Solution

v1 = 0 [because it started to break free]
a = -5.2m/s^2 [because of the sign convention down]
Δt = 5.0s
v2 = ? [because it is finding velocity after 5.0s]

ok it was v2 = 0 + (-5.2m/s^2)(5.0s)
v2 = -26 m/s

Am I correct or have a done a simple mistake that would impact my answer?

 

[mgb_phys]

Correct