How Fast Does a Cylinder Roll Down an Inclined Plane?

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SUMMARY

The discussion focuses on calculating the linear speed of a solid cylinder with a mass of 3.0 kg and a radius of 0.2 m as it rolls down a 15-degree inclined plane from a height of 1.2 m. The moment of inertia is given as I = 0.5MR^2, which is 0.6 kg·m² for this cylinder. The solution involves applying the conservation of energy principle, where the potential energy at the top converts into both translational and rotational kinetic energy at the bottom. The final linear speed can be derived using the equation for kinetic energy of a rigid body that translates and rotates.

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irony416
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Homework Statement


Problem:

A solid cylinder of mass 3.0 kg and radius 0.2 m starts from rest at the top of a ramp, inclined 15 degrees, and rolls to the bottom without slipping. (I = 0.5MR^2). The upper end of the ramp is 1.2 m higher than the lower end. Find the lindear speed of the cylinder when it reaches the bottom of the ramp.

Homework Equations



Equations:
I = 0.5MR^2 = 0.6

The Attempt at a Solution


Do I use angular momentum here? Really have no idea. Thanks.
 
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Use conservation of energy. What is the kinetic energy of a rigid body that both translates and rotates?
 

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