How Fast Does Ozone Travel After Collision?

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SUMMARY

The discussion focuses on calculating the velocity of an ozone molecule formed from a collision between a 32-u oxygen molecule (O2) and a 16-u oxygen atom. The initial velocities are 580 m/s in the +x-direction for the O2 molecule and 870 m/s at a 27° angle for the oxygen atom. Using the conservation of momentum, the final velocity of the ozone molecule is determined to be 645 m/s in the x-direction. The analysis emphasizes the importance of considering both x and y components of momentum in such collisions.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Basic knowledge of vector components in physics
  • Familiarity with mass units (u) and their conversions
  • Ability to perform trigonometric calculations for vector resolution
NEXT STEPS
  • Study the principles of momentum conservation in two-dimensional collisions
  • Learn about vector addition and resolution in physics
  • Explore the properties and behavior of ozone molecules in different states
  • Investigate the effects of angle and mass on collision outcomes
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for practical examples of momentum conservation in action.

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Homework Statement



A 32-u oxygen molecule (O2) moving in the +x-direction at 580 m/s collides with an oxygen atom (mass 16 u) moving at 870 m/s at 27° to the x-axis. The particles stick together to form an ozone molecule. Find the ozone’s velocity.


Homework Equations





The Attempt at a Solution



m1 = 32 u,
v1 = 580i m/s,
m2 = 16 u,

v2 =870(cos(27) i + sin(27) j) m/s

m1 v1 + m2 v2 =(m1 + m2)V

V = (m1 v1+ m2 v2)/(m1+ m2) = (645 i) m/s

Answer = 645 i m/s

Does that look right?
 
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Conservation of momentum must hold for all components. You calculated the x component of velocity of the ozone molecule. Do you think it has zero y component of velocity?

ehild
 

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