Collision problem: Two hockey pucks collide and stick together....

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Homework Help Overview

The discussion revolves around a collision problem involving two hockey pucks that collide at a 90-degree angle and stick together. The original poster presents initial conditions, including masses and velocities of the pucks, and seeks to determine their speed and direction after the collision.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the application of momentum conservation in a two-dimensional collision context. Some question the original poster's application of scalar speeds to a vector problem, while others seek clarification on the correct approach to determine the resulting speed and angle after the collision.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's attempts and encouraging further questions. There is an acknowledgment of the complexity of the problem, particularly regarding the two-dimensional nature of the collision.

Contextual Notes

Participants note that the original poster's solution may have misapplied concepts related to vector velocities and scalar speeds. The problem is framed within the constraints of a homework assignment, which may limit the information available for a complete analysis.

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Homework Statement


Two hockey pucks collide in a 90 degree angle and stick to each other. What's the speed of the hockey pucks after the collision and in what angle are the pucks moving in.

Homework Equations


m1=0.71kg
m2=0.52kg
v1=1.6m/s
v2=3.8m/s

The Attempt at a Solution


m1v1+m2v2=v(m1+m2)
=0.71kg*1.6m/s+0.52kg*3.8m/s=(0.71kg+0.52kg)*v
=v=(3.1kgm/s)/1.23kg=2.52m/s
 
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Hi Jeemeli and welcome to PF.

Is there something you wish to know about this? If so, please ask.
 
kuruman said:
Hi Jeemeli and welcome to PF.

Is there something you wish to know about this? If so, please ask.
My solution was wrong, Id like to know how to get the right answer
 
Jeemeli said:
m1v1+m2v2=v(m1+m2)
=0.71kg*1.6m/s+0.52kg*3.8m/s=(0.71kg+0.52kg)*v
You've gone from a correct formula involving vector velocities and applied it to scalar speeds.

If you walk 1.136 meters north and 1.976 meters east, how far from your starting position will you be as the crow flies?
 
Jeemeli said:
My solution was wrong, Id like to know how to get the right answer
In short, this is a two-dimensional collision.
 

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