How fast does the disk move when pulled by a string?

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SUMMARY

The discussion focuses on the dynamics of a solid uniform disk with a mass of 21.0 kg and a radius of 85.0 cm, subjected to a constant force of 35.0 N applied via a string. The calculations involve determining the linear velocity after moving 3.2 m, the angular velocity, and the amount of string unwrapped. The correct approach for finding the linear acceleration uses Newton's second law, leading to a final linear velocity of 4.6 m/s and an angular velocity derived from the relationship between linear and angular motion.

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1. A solid uniform disk of mass 21.0 kg and radius 85.0 cm is at rest flat on a frictionless surface. A string is wrapped around the rim of the disk and a constant force of 35.0 N is applied to the string. The string does not slip on the rim.
(A) When the disk has moved a distance of 3.2 m, determine how fast it is moving.
(B) How fast it is spinning (in radians per second).
(C) How much string has unwrapped from around the rim.

Homework Equations


τ=RF
τ=Iα
I=.5mR^{2}
a=Rα
v^{2}=v^{2}_{0}+2ax
v=Rω

The Attempt at a Solution


(A) τ=RF=(35)(.85)=29.75
I=(.5)(21)(.85)^{2}=7.58625
α=τ/I=29.75/7.58625=3.92
a=(.85)(3.92)=3.33
v=\sqrt{0+(2)(3.33)(3.2)}=4.6
This is how I did the problem but it is incorrect.

(B)v=Rω
I want to use this formula to find the angular velocity but my velocity is incorrect.

(C)I was thinking of using this formula: θ=(ω^{2}-ω^{2}_{0})/2α

Can somebody please help me?
 
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kritzy said:
A solid uniform disk of mass 21.0 kg and radius 85.0 cm is at rest flat on a frictionless surface. A string is wrapped around the rim of the disk and a constant force of 35.0 N is applied to the string. The string does not slip on the rim.
(A) When the disk has moved a distance of 3.2 m, determine how fast it is moving.

τ=RF
τ=Iα

Hi kritzy! :smile:

For (A), use the ordinary (linear) version of Newton's second law :wink:
 
tiny-tim said:
Hi kritzy! :smile:

For (A), use the ordinary (linear) version of Newton's second law :wink:

I figured it out. Thank you for the hint.:smile:
 

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