How Fast is the Ball After a Perfectly Elastic Collision?

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SUMMARY

The discussion focuses on calculating the speed of a 20g ball after a perfectly elastic collision with a 100g block attached to a spring with a spring constant of 20N/m. The initial velocity of the ball is 5.0m/s. The key conclusion is that the speed of the ball after the collision is 3.3m/s, as confirmed by the provided answer. The solution involves applying the principles of conservation of momentum and kinetic energy during elastic collisions.

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A 100gram block is attached to the end of a spring on a frictionless table that has a spring constant of 20N/m. The other end of the spring is attached to the wall. A 20g ball is thrown at the block with a velocity of 5.0m/s.

If the collision is perfectly elastic, what is the ball's speed immediately after the collision.

I am unsure about how to solve this, I know that an elastic collision is one in which energy is conserved so the initial Kinetic energy of the ball is the systems total energy after collision. But what to do from there?



PS: answer in book says 3.3m/s
 
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But what to do from there?
Add momentum conservation, write down formulas and solve.
 

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