Perfectly elastic collision between two electrons in ⊥ B-field

In summary, the conversation discusses the inclusion of electrical potential energy in a problem involving conservation of energy, and the reason for its exclusion due to the negligible change in potential energy over a small time interval. There is also a clarification on the internal structure of electrons and the potential for energy loss in elastic electron-electron collisions. The final radii in the problem are measured when the electrons are far apart, resulting in zero potential energy.
  • #1
ChiralSuperfields
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Homework Statement
Please see below
Relevant Equations
Please see below
For this problem,
1673752127546.png

The solution is,
1673752152479.png

However, is the reason why they don't include electrical potential energy because the time interval for which we are applying conservation of energy over is very small so the change in electric potential energy is negligible?

Also, when they said, "electrons have no internal structure to absorb energy", would it not be more concise to say "The internal structure of electrons cannot absorb kinetic energy"?

My statement reflects that electrons do have internal structure consist of quarks which can absorb and emit energy by via photonic emission.

Many thanks!
 
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And even it it where protons in this problem, you can assume that there is no change in their internal energy because we need quite high energy to change the quark configuration in them. If electrons have subparticles (preons or whatever) we still assume that the energies involved in this problem is not large enough to resolve that. It is written in the problem that they undergo elastic collision. Thus, there is no change in internal energy.
 
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  • #5
malawi_glenn said:
And even it it where protons in this problem, you can assume that there is no change in their internal energy because we need quite high energy to change the quark configuration in them. If electrons have subparticles (preons or whatever) we still assume that the energies involved in this problem is not large enough to resolve that. It is written in the problem that they undergo elastic collision. Thus, there is no change in internal energy.
Thank you for your help @malawi_glenn !
 
  • #6
Callumnc1 said:
However, is the reason why they don't include electrical potential energy because the time interval for which we are applying conservation of energy over is very small so the change in electric potential energy is negligible?
The final radii are measured when the electrons are far apart - so their potential energy is zero. You are determining the kinetic energy of the incident electron when the initial separation was large, so the intial potential energy was also zero. (The question could have been a bit clearer about this!)

FWIW, although electrons have no internal structure, that does not mean electron-electron collisions are necessarily elastic. Loss of (kinetic) energy can occur due to the production of EM radiation. For example that’s how an X-ray tube produces X-rays – ‘bremsstrahlung’. But you can assume the effect is negligible in this question, because you are told the collision is elastic.
 
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  • #7
Steve4Physics said:
The final radii are measured when the electrons are far apart - so their potential energy is zero. You are determining the kinetic energy of the incident electron when the initial separation was large, so the intial potential energy was also zero. (The question could have been a bit clearer about this!)

FWIW, although electrons have no internal structure, that does not mean electron-electron collisions are necessarily elastic. Loss of (kinetic) energy can occur due to the production of EM radiation. For example that’s how an X-ray tube produces X-rays – ‘bremsstrahlung’. But you can assume the effect is negligible in this question, because you are told the collision is elastic.
Ok thank you for your help @Steve4Physics !
 
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What is a perfectly elastic collision between two electrons?

A perfectly elastic collision between two electrons refers to a scenario in which two electrons collide with each other and there is no loss of kinetic energy. This means that after the collision, the electrons will continue moving with the same speed and direction as before the collision.

What is a ⊥ B-field?

A ⊥ B-field, or a perpendicular magnetic field, is a magnetic field that is oriented at a 90-degree angle to the direction of motion of the electrons. This type of magnetic field can affect the motion of charged particles, such as electrons, that are moving through it.

How does a perpendicular B-field affect the collision between two electrons?

A perpendicular B-field can cause the electrons to experience a force that is perpendicular to their motion, which can alter the direction of their paths. This can result in a change in the direction of the electrons' motion after the collision.

Is a perfectly elastic collision between two electrons in a ⊥ B-field possible?

Yes, a perfectly elastic collision between two electrons in a ⊥ B-field is possible. This occurs when the electrons collide at a specific angle and with a specific velocity, resulting in no loss of kinetic energy and a change in direction due to the influence of the B-field.

What other factors can affect the outcome of a perfectly elastic collision between two electrons in a ⊥ B-field?

The angle and velocity at which the electrons collide, as well as the strength of the B-field, can all affect the outcome of a perfectly elastic collision between two electrons. Additionally, the mass and charge of the electrons can also play a role in the collision.

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